This preview shows page 1. Sign up to view the full content.
86. From mechanical energy conservation (or simply using Eq. 216 with
G
ag
=
downward) we obtain
2
2
2(9.8 m/s )(1.5 m)
5.4 m/s
vg
h
==
=
for the speed just as the body makes contact with the ground.
(a) During the compression of the body, the center of mass must decelerate over a
distance
d
= 0.30 m. Choosing +
y
downward, the deceleration
a
is found using Eq. 216.
02
2
54
2030
2
22
=+
¡
=−
va
d
a
v
d
.
(. )
which yields
a
49 m s
2
. Thus, the magnitude of the net (vertical) force is
ma
= 49
m
in SI units, which (since 49 m/s
2
= 5(9.8 m/s
2
) = 5
g
) can be expressed as 5
mg
.
(b) During the deceleration process, the forces on the dinosaur are (in the vertical
direction)
N
F
G
and
mg
G
. If we choose +
y
upward, and use the final result from part (a), we
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy

Click to edit the document details