92. One approach is to choose a movingcoordinate system which travels the center of mass of the body, and another is to do a little extra algebra analyzing it in the original coordinate system (in which the speed of the m= 8.0 kg mass is v0= 2 m/s, as given). Our solution is in terms of the latter approach since we are assuming that this is the approach most students would take. Conservation of linear momentum (along the direction of motion) requires 0112212(8.0)(2.0)(4.0)(4.0)mvm vm vvv=+¡which leads to vv214=−in SI units (m/s). We require 222222112 2012111116(4.0)(4.0)(8.0)(2.0)2222Kmvmvmvvv§·§
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