92. One approach is to choose a
moving
coordinate system which travels the center of
mass of the body, and another is to do a little extra algebra analyzing it in the original
coordinate system (in which the speed of the
m
= 8.0 kg mass is
v
0
= 2 m/s, as given).
Our solution is in terms of the latter approach since we are assuming that this is the
approach most students would take. Conservation of linear momentum (along the
direction of motion) requires
01
12
2
1
2
(8.0)(2.0)
(4.0)
(4.0)
mv
m v
m v
v
v
=+
¡
which leads to
vv
21
4
=−
in SI units (m/s). We require
22
2
2
2
2
11
2 2
0
1
2
1
1
1
1
16
(4.0)
(4.0)
(8.0)(2.0)
2
2
2
2
Km
v
m
v
m
v
v
v
§·
§
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Center Of Mass, Mass

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