ch09-p093 - 93. (a) The initial momentum of the car is pi =...

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and the final momentum is G p f =⋅ 7400kg m s i. b g # The impulse on it equals the change in its momentum: () 3 ˆˆ 7.4 10 N s i j . fi Jp p =− = × G GG (b) The initial momentum of the car is G p i 7400kg m s i b g # and the final momentum is G p f = 0. The impulse acting on it is 3 ˆ ( 7.4 10 N s)i. p = −× G (c) The average force on the car is G G G F p t J t avg kg m s i j 4.6s Ni j === ⋅− Δ ΔΔ 7400 1600 b g e j b g e j ## and its magnitude is 3 avg 1600N 2 2.3 10 N. F == × (d) The average force is G G F J t avg kg m s i s Ni −⋅ × =− × Δ 7400 350 10 21 10 3 4 b
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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