ch09-p103

# ch09-p103 - 103 The diagram below shows the situation as...

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v v = + = ° = 2 12 210 30 3 0 693 0 22 cos cos (c o s cos .. θ ms ) ms (a) The discussion and computation above determines the final speed of ball 2 (as labeled in Fig. 9-83) to be 6.9 m/s. (b) The direction of ball 2 is at 30° counterclockwise from the + x axis. (c) Similarly, the final speed of ball 3 is 6.9 m/s. (d) The direction of ball 3 is at 30° counterclockwise from the + x axis. 103. The diagram below shows the situation as the incident ball (the left-most ball) makes contact with the other two. It exerts an impulse of the same magnitude on each ball, along the line that joins the centers of the incident ball and the target ball. The target balls leave the collision along those lines, while the incident ball leaves the collision along the x axis. The three dotted lines that join the centers of the balls in contact form an equilateral triangle, so both of the angles marked are 30°. Let v 0 be the velocity of the incident ball before the collision and V be its velocity afterward. The two target balls leave the collision with the same

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## This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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ch09-p103 - 103 The diagram below shows the situation as...

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