ch09-p105 - 105. (a) We place the origin of a coordinate...

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Thus, a gm m mm com 2 2 m/s g g g = + = + 21 2 12 2 2 2 2 9 8 520 480 480 520 g 16 10 b g bg c h . .. The acceleration is downward. 105. (a) We place the origin of a coordinate system at the center of the pulley, with the x axis horizontal and to the right and with the y axis downward. The center of mass is halfway between the containers, at x = 0 and y = A , where A is the vertical distance from the pulley center to either of the containers. Since the diameter of the pulley is 50 mm, the center of mass is at a horizontal distance of 25 mm from each container. (b) Suppose 20 g is transferred from the container on the left to the container on the right. The container on the left has mass m 1 = 480 g and is at x 1 = –25 mm. The container on the right has mass m 2 = 520 g and is at x 2 = +25 mm. The x coordinate of the center of mass is then x mx com g g g 520 g mm. = + + = −+ + = 11 2 2 480 25 520 25 480 10 b g b g . The y coordinate is still A . The center of mass is 26 mm from the lighter container, along the line that joins the bodies.
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