ch09-p105

# ch09-p105 - 105. (a) We place the origin of a coordinate...

This preview shows page 1. Sign up to view the full content.

Thus, a gm m mm com 2 2 m/s g g g = + = + 21 2 12 2 2 2 2 9 8 520 480 480 520 g 16 10 b g bg c h . .. The acceleration is downward. 105. (a) We place the origin of a coordinate system at the center of the pulley, with the x axis horizontal and to the right and with the y axis downward. The center of mass is halfway between the containers, at x = 0 and y = A , where A is the vertical distance from the pulley center to either of the containers. Since the diameter of the pulley is 50 mm, the center of mass is at a horizontal distance of 25 mm from each container. (b) Suppose 20 g is transferred from the container on the left to the container on the right. The container on the left has mass m 1 = 480 g and is at x 1 = –25 mm. The container on the right has mass m 2 = 520 g and is at x 2 = +25 mm. The x coordinate of the center of mass is then x mx com g g g 520 g mm. = + + = −+ + = 11 2 2 480 25 520 25 480 10 b g b g . The y coordinate is still A . The center of mass is 26 mm from the lighter container, along the line that joins the bodies.
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online