ch09-p107 - + x-axis. (c) A similar calculation using Eq....

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107. (a) Noting that the initial velocity of the system is zero, we use Eq. 9-19 and Eq. 2- 15 (adapted to two dimensions) to obtain d = 1 2 © ¨ § ¹ ¸ · F 1 + F 2 m 1 + m 2 t 2 = 1 2 © ¨ § ¹ ¸ · –2i ^ + j ^ 0.006 (0.002) 2 which has a magnitude of 0.745 mm. (b) The angle of d is 153 ° counterclockwise from
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Unformatted text preview: + x-axis. (c) A similar calculation using Eq. 2-11 (adapted to two dimensions) leads to a center of mass velocity of v = 0.7453 m/s at 153 . Thus, the center of mass kinetic energy is K com = 1 2 ( m 1 + m 2 ) v 2 = 0.00167 J....
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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