ch09-p108 - 108. (a) The change in momentum (taking upwards...

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108. (a) The change in momentum (taking upwards to be the positive direction) is Δ p = (0.550 kg)[ (3 m/s)j ^ – (–12 m/s)j ^ ] = (+8.25 kg . m/s) j ^ . (b) By the impulse-momentum theorem (Eq. 9-31)
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