110. (a) Since the initial momentum is zero, then the final momenta must add (in the vector sense) to 0. Therefore, with SI units understood, we have()312 11222762761919ˆˆ16.7 106.00 10 i8.35 108.00 10 j1.00 10i 0.67 10j kg m/s.pppmvmv−−=− −=−−××−×−××+×⋅GGGGG(b) Dividing by m3= 11.7
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.