This preview shows page 1. Sign up to view the full content.
Unformatted text preview: Later, when the car (about to make the jump) is near the left end of the boat (which has moved from the shore an amount x ), the value of the system center of mass is still 8.5 m. The car (at this moment) is thought of as a pointmass 1.5 m from the left end, so we must have x com = m 1 x 1 + m 2 x 2 m 1 + m 2 = (1500 kg)( x + 1.5 m) + (4000 kg)(7 m + x ) 1500 kg + 4000 kg = 8.5 m. Solving this for x , we find x = 3.0 m....
View
Full
Document
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Center Of Mass, Mass

Click to edit the document details