ch09-p114 - t . Thus, our result for the magnitude of the...

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114. (a) The magnitude of the impulse is equal to the change in momentum: J = mv m (– v ) = 2 mv = 2(0.140 kg)(7.80 m/s) = 2.18 kg m/s (b) Since in the calculus sense the average of a function is the integral of it divided by the corresponding interval, then the average force is the impulse divided by the time
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Unformatted text preview: t . Thus, our result for the magnitude of the average force is 2 m v/ t . With the given values, we obtain F avg = 2(0.140 kg)(7.80 m/s) 0.00380 s = 575 N ....
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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