126. The momentum before the collision (with +xrightward) is (.6 0 kg)(8.0 m / s) (4.0 kg)(2.0 m / s)56 kg m / s.+=⋅(a) The total momentum at this instant is ( .6 0 kg)(6.4 m / s) (4.0 kg)+Gv. Since this must equal the initial total momentum (56, using SI units), then we find 4.4 m/s.v=G(b) The initial kinetic energy was 126040kg)(8.0 m / s)1
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.