126. The momentum before the collision (with +
x
rightward) is
(.
6 0 kg)(8.0 m / s) (4.0 kg)(2.0 m / s)
56 kg m / s.
+=
⋅
(a) The total momentum at this instant is ( .
6 0 kg)(6.4 m / s) (4.0 kg)
+
G
v
. Since this must
equal the initial total momentum (56, using SI units), then we find
4.4 m/s.
v
=
G
(b) The initial kinetic energy was
1
2
60
40
kg)(8.0 m / s)
1
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Momentum

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