ch09-p127 - e and v p being their respective speeds, we...

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127. (a) The initial momentum of the system is zero, and it remains so as the electron and proton move toward each other. If p e is the magnitude of the electron momentum at some instant (during their motion) and p p is the magnitude of the proton momentum, then these must be equal (and their directions must be opposite) in order to maintain the zero total momentum requirement. Thus, the ratio of their momentum magnitudes is +1. (b) With v
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Unformatted text preview: e and v p being their respective speeds, we obtain (from the p e = p p requirement) m e v e = m p v p v e / v p = m p / m e 1830 1.83 10 3 . (c) We can rewrite K = 1 2 m v 2 as K = 1 2 p 2 / m which immediately leads to K e / K p = m p / m e 1830 1.83 10 3 . (d) Although the speeds (and kinetic energies) increase, they do so in the proportions indicated above. The answers stay the same....
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