On the other hand, as the cat lands on the second sled, it sticks to it and the system (sled
plus cat) moves forward with a speed
2
0.4205 m/s.
i
f
mv
v
Mm
==
+
When the cat makes the second jump back to the first sled with a speed
v
i
, momentum
conservation implies
22
()
2
f
fi
i
i
Mv
mv
M
m v
mv
mv
mv
=++
=+=
which yields
2
2
0.975 m/s.
i
ff
mv
v
M
After the cat lands on the first sled, the entire system (cat and the sled) again moves
together. By momentum conservation, we have
11
2
f
i
i
M
m v
mv
Mv
mv
mv
mv
+=
+
=
+
=
or
1
2
0.841 m/s.
i
ff
mv
v
+
(a) From the above, we conclude that the first sled moves with a speed
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Mass, Momentum

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