ch09-p136

# ch09-p136 - 136 Let M = 22.7 kg and m = 3.63 be the mass of...

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On the other hand, as the cat lands on the second sled, it sticks to it and the system (sled plus cat) moves forward with a speed 2 0.4205 m/s. i f mv v Mm == + When the cat makes the second jump back to the first sled with a speed v i , momentum conservation implies 22 () 2 f fi i i Mv mv M m v mv mv mv =++ =+= which yields 2 2 0.975 m/s. i ff mv v M After the cat lands on the first sled, the entire system (cat and the sled) again moves together. By momentum conservation, we have 11 2 f i i M m v mv Mv mv mv mv += + = + = or 1 2 0.841 m/s. i ff mv v + (a) From the above, we conclude that the first sled moves with a speed
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## This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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