On the other hand, as the cat lands on the second sled, it sticks to it and the system (sled plus cat) moves forward with a speed 20.4205 m/s.ifmvvMm==+When the cat makes the second jump back to the first sled with a speed vi, momentum conservation implies 22()2ffiiiMvmvMm vmvmvmv=++=+=which yields 220.975 m/s.iffmvvMAfter the cat lands on the first sled, the entire system (cat and the sled) again moves together. By momentum conservation, we have 112fiiMm vmvMvmvmvmv+=+=+=or120.841 m/s.iffmvv+(a) From the above, we conclude that the first sled moves with a speed
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.