13. We take
t
= 0 at the start of the interval and take the sense of rotation as positive.
Then at the end of the
t
= 4.0 s interval, the angular displacement is
θω
α
=+
0
1
2
2
tt
. We
solve for the angular velocity at the start of the interval:
()
2
2
1
2
1
2
2
0
120 rad
3.0 rad/s
4.0 s
24 rad/s.
4.0 s
t
t
θα
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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