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Unformatted text preview: 27. (a) In the time light takes to go from the wheel to the mirror and back again, the wheel turns through an angle of θ = 2π/500 = 1.26 × 10–2 rad. That time is
t= 2 2(500 m) = = 3.34 × 10 −6 s c 2.998 × 108 m / s so the angular velocity of the wheel is ω= θ
t = . 126 × 10−2 rad . = 38 × 103 rad / s. −6 3.34 × 10 s (b) If r is the radius of the wheel, the linear speed of a point on its rim is
v = ω r = 3.8 × 103 rad/s ( ) ( 0.050 m ) = 1.9 ×10 2 m/s. ...
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Light

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