32. (a) A complete revolution is an angular displacement of Δθ= 2πrad, so the angular velocity in rad/s is given by ω= Δ/T= 2π/T. The angular acceleration is given by α==−ddtTdTdt22π.For the pulsar described in the problem, we have dTdt=××=×−−126 10316 10400 105713....s/yTherefore,=−FHGIKJ×=−×−−20 03323 10139π(.)..s)rad / s22The negative sign indicates that the angular acceleration is opposite the angular velocity and the pulsar is slowing down. (b) We solve = 0+ tfor the time twhen = 0: 103092228.3 10s2.6 10
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