ch10-p036 - ≈ 7.1(b If instead the outermost particle is...

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36. (a) Eq. 10-33 gives I total = md 2 + m (2 d ) 2 + m (3 d ) 2 = 14 md 2 . If the innermost one is removed then we would only obtain m (2 d ) 2 + m (3 d ) 2 = 13 md 2 . The percentage difference between these is (13 – 14)/14 = 0.0714
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Unformatted text preview: ≈ 7.1%. (b) If, instead, the outermost particle is removed, we would have md 2 + m (2 d ) 2 = 5 md 2 . The percentage difference in this case is 0.643 ≈ 64%....
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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