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Im r ii == + = ⋅ ¦ 22 2 2050 10 50 60 .. . . kg m m kg m 2 bg ch (c) Now, two masses are on the axis (with r = 0) and the other two are a distance (1.0 m) (1.0 m) r =+ away. Now we obtain 2 2.0 kg m . I =⋅ 40. (a) We show the figure with its axis of rotation (the thin horizontal line). We note that each mass is r = 1.0 m from the axis. Therefore, using Eq. 10-26, we obtain
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