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Im
r
ii
==
+
=
⋅
¦
22
2
2050
10
50
60
..
.
.
kg
m
m
kg m
2
bg
ch
(c) Now, two masses are on the axis (with
r
= 0) and the other two are a distance
(1.0 m)
(1.0 m)
r
=+
away. Now we obtain
2
2.0 kg m .
I
=⋅
40. (a) We show the figure with its axis of rotation (the
thin horizontal line).
We note that each mass is
r
= 1.0 m from the axis.
Therefore, using Eq. 1026, we obtain
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Mass

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