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Unformatted text preview: OO OO with the one at O in the middle, then the total rotational inertia is I = 5( 1 2 mR 2 ) + 2( m (2 R ) 2 + m (4 R ) 2 ). The pattern is now clear and we can write down the total I for the collection of fifteen disks: I = 15( 1 2 mR 2 ) + 2( m (2 R ) 2 + m (4 R ) 2 + m (6 R ) 2 + + m (14 R ) 2 ) = 2255 2 mR 2 . The generalization to N disks (where N is assumed to be an odd number) is I = 1 6 (2 N 2 + 1) NmR 2 . In terms of the total mass ( m = M /15) and the total length ( R = L /30), we obtain...
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Inertia

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