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55. (a) We use constant acceleration kinematics. If down is taken to be positive and
a
is
the acceleration of the heavier block
m
2
, then its coordinate is given by
ya
t
=
1
2
2
, so
a
y
t
==
=
×
−
2
2 0 750
500
600 10
22
(.
)
)
..
m
s
m/s
Block 1 has an acceleration of
6.00
×
10
–2
m/s
2
upward.
(b) Newton’s second law for block 2 is
2
mg T
ma
−=
, where
m
2
is its mass and
T
2
is the
tension force on the block. Thus,
()
2
(
)
(0.500 kg) 9.8 m/s
6.00 10
m/s
4.87 N.
Tm
g
a
−
=−
=
−
×
=
(c) Newton’s second law for block 1 is
11
1
,
−
where
T
1
is the tension force on
the block. Thus,
2
(
)
(0.460 kg) 9.8 m/s
6.00 10
m/s
4.54 N.
ga
−
=+
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Acceleration

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