ch10-p055 - 55. (a) We use constant acceleration...

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55. (a) We use constant acceleration kinematics. If down is taken to be positive and a is the acceleration of the heavier block m 2 , then its coordinate is given by ya t = 1 2 2 , so a y t == = × 2 2 0 750 500 600 10 22 (. ) ) .. m s m/s Block 1 has an acceleration of 6.00 × 10 –2 m/s 2 upward. (b) Newton’s second law for block 2 is 2 mg T ma −= , where m 2 is its mass and T 2 is the tension force on the block. Thus, () 2 ( ) (0.500 kg) 9.8 m/s 6.00 10 m/s 4.87 N. Tm g a =− = × = (c) Newton’s second law for block 1 is 11 1 , where T 1 is the tension force on the block. Thus, 2 ( ) (0.460 kg) 9.8 m/s 6.00 10 m/s 4.54 N. ga =+
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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