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Unformatted text preview: 2 , then Eq. 1045 gives   = 2.955 3.0 rad/s 2 . (b) Now we have another contribution (1.4 m 300 N) to the net torque, so  net  = (70 kg)(9.8 m/s 2 )(0.28 m) + (1.4 m)(300 N) = (65 kgm 2 )   which leads to   = 9.4 rad/s 2 ....
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 Spring '08
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 Physics, Force

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