ch10-p064 - f = 60 rad/s and i = 40 rad/s. This gives W =...

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64. (a) Eq. 10-33 gives I total = md 2 + m (2 d ) 2 + m (3 d ) 2 = 14 md 2 , where d = 0.020 m and m = 0.010 kg. The work done is W = Δ K = 1 2 I ω f 2 1 2 I i 2 , where f = 20 rad/s and i = 0. This gives W = 11.2 mJ. (b) Now, f = 40 rad/s and i = 20 rad/s, and we get W = 33.6 mJ. (c) In this case,
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Unformatted text preview: f = 60 rad/s and i = 40 rad/s. This gives W = 56.0 mJ. (d) Eq. 10-34 indicates that the slope should be 1 2 I . Therefore, it should be 7 md 2 = 2.80 10 5 J . s 2 / rad 2 ....
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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