ch10-p066 - 66. From Table 10-2, the rotational inertia of...

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2 2 11 22 3 32 2 1(/ )( 2 / 3) 2(9.8)(0.82) 1.4 m/s 1 3.0 10 /((0.60)(0.050) ) 2(4.5)/3(0.60) IM r mgh gh v mI m r M m == ++ + + + 66. From Table 10-2, the rotational inertia of the spherical shell is 2 MR 2 /3, so the kinetic energy (after the object has descended distance h ) is KM R I m v = F H G I K J 1 2 2 3 1 2 1 2 sphere pulley 2 2 ωω . Since it started from rest, then this energy must be equal (in the absence of friction) to the
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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