ch10-p067 - 67. (a) We use conservation of mechanical...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
67. (a) We use conservation of mechanical energy to find an expression for ω 2 as a function of the angle θ that the chimney makes with the vertical. The potential energy of the chimney is given by U = Mgh , where M is its mass and h is the altitude of its center of mass above the ground. When the chimney makes the angle with the vertical, h = ( H /2) cos . Initially the potential energy is U i = Mg ( H /2) and the kinetic energy is zero. The kinetic energy is 1 2 2 I when the chimney makes the angle with the vertical, where I is its rotational inertia about its bottom edge. Conservation of energy then leads to MgH Mg H I MgH I / ( /) /) ( 22 1 2 =+ ¡ =− cos 1 2 (c o s ) . 2 θω ω I = MH 2 /3 (found using Table 10-2(e) with the parallel axis theorem). Thus 2 33 ( 9 . 8 0 m / s ) (1 cos ) (1 cos35.0 ) 0.311 rad/s. 55.0 m g H ωθ
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online