ch10-p086 - 86. (a) Using Eq. 10-15, we have 60.0 rad = 2...

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Unformatted text preview: 86. (a) Using Eq. 10-15, we have 60.0 rad = 2 (ω1 + ω2)(6.00 s) . With ω2 = 15.0 rad/s, then ω1 = 5.00 rad/s. (b) Eq. 10-12 gives α = (15.0 rad/s – 5.0 rad/s)/(6.00 s) = 1.67 rad/s2. (c) Interpreting ω now as ω1 and θ as θ1 = 10.0 rad (and ωo = 0) Eq. 10-14 leads to 1 θo = – ω12 + θ1 = 2.50 rad . 2α ...
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