ch10-p087 - 87. With rightward positive for the block and...

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sign from the block’s acceleration (which we simply denote as a ); that is, a t = – a . Applying Newton’s second law to the block leads to PT m a −= , where 2.0 kg. m = Applying Newton’s second law (for rotation) to the wheel leads to TR I α , where 2 0.050 kg m . I =⋅ Noting that R = a t = – a , we multiply this equation by R and obtain 2 2 . I TR Ia T a R ¡ = Adding this to the above equation (for the block) leads to 2 (/ ) . Pm I R a =+ Thus, a = 0.92 m/s
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