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sign from the block’s acceleration (which we simply denote as
a
); that is,
a
t
= – a
.
Applying Newton’s second law to the block leads to
PT m
a
−=
, where
2.0 kg.
m
=
Applying Newton’s second law (for rotation) to the wheel leads to
TR
I
α
, where
2
0.050 kg m .
I
=⋅
Noting that
R
= a
t
= – a
, we multiply this equation by
R
and obtain
2
2
.
I
TR
Ia
T
a
R
−
¡
=
Adding this to the above equation (for the block) leads to
2
(/
)
.
Pm
I
R
a
=+
Thus,
a
= 0.92 m/s
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 Spring '08
 Any
 Physics, Acceleration

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