ch10-p090 - 90. We use conservation of mechanical energy....

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90. We use conservation of mechanical energy. The center of mass is at the midpoint of the cross bar of the H and it drops by L /2, where L is the length of any one of the rods. The gravitational potential energy decreases by MgL /2, where M is the mass of the body. The initial kinetic energy is zero and the final kinetic energy may be written 1 2 2 I ω , where I is the rotational inertia of the body and is its angular velocity when it is vertical. Thus, 02 2 =− + ¡ = MgL I MgL I // . 1 2 ωω Since the rods are thin the one along the axis of rotation does not contribute to the
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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