Unformatted text preview: 95. The centripetal acceleration at a point P which is r away from the axis of rotation is given by Eq. 1023: a = v 2 / r = ω 2 r , where v = ω r , with ω = 2000 rev/min ≈ 209.4 rad/s. (a) If points A and P are at a radial distance rA=1.50 m and r = 0.150 m from the axis, the difference in their acceleration is Δa = a A − a = ω 2 (rA − r ) = (209.4 rad/s) 2 (1.50 m − 0.150 m) ≈ 5.92 ×104 m/s 2 (b) The slope is given by a / r = ω 2 = 4.39 ×104 / s 2 . ...
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Acceleration

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