ch10-p112 - 112(a The particle at A has r = 0 with respect...

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Im r m L m L ii == + =⋅ ¦ 22 2 di 0.20 kg m 2 . (b) One imagines rotating the figure (about point A ) clockwise by 90° and noting that the center of mass has fallen a distance equal to L as a result. If we let our reference position for gravitational potential be the height of the center of mass at the instant AB swings through vertical orientation, then () 00 0 04 0 . KU KU m g hK += + ¡ + Since h 0 = L = 0.50 m, we find K = 3.9 J. Then, using Eq. 10-34, we obtain
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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