ImrmLmLii==+=⋅¦222di0.20 kg m2.(b) One imagines rotating the figure (about point A) clockwise by 90° and noting that the center of mass has fallen a distance equal to Las a result. If we let our reference position for gravitational potential be the height of the center of mass at the instant ABswings through vertical orientation, then ()000040.KU KUmghK+=+¡+Sinceh0= L= 0.50 m, we find K= 3.9 J. Then, using Eq. 10-34, we obtain
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.