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For a uniform disk (relative to its center of mass) Im R = 1 2 2 (Table 10-2(c)). Since the wheels roll without sliding ω = v / R (Eq. 11-2). Thus the numerator of our fraction is 44 1 2 2 22 2 2 R v R mv = F H G I K J F H G I K J = and the fraction itself becomes () 2 210 1 fraction 0.020. 2 2 1000 50 mv m Mv mv M m == = = = ++ The wheel radius cancels from the equations and is not needed in the computation. 3. Let M be the mass of the car (presumably including the mass of the wheels) and v be its speed. Let
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