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For a uniform disk (relative to its center of mass)
Im
R
=
1
2
2
(Table 102(c)). Since the
wheels roll without sliding
ω
=
v
/
R
(Eq. 112). Thus the numerator of our fraction is
44
1
2
2
22
2
2
R
v
R
mv
=
F
H
G
I
K
J
F
H
G
I
K
J
=
and the fraction itself becomes
()
2
210
1
fraction
0.020.
2
2
1000
50
mv
m
Mv
mv
M
m
==
=
=
=
++
The wheel radius cancels from the equations and is not needed in the computation.
3. Let
M
be the mass of the car (presumably including the mass of the wheels) and
v
be
its speed. Let
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy, Inertia, Kinetic Energy, Mass

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