which leads to 184.108.40.206 .hRrR=−≈With R= 14.0 cm , we have h= (2.7)(14.0 cm) = 37.8 cm. (b) The energy considerations shown above (now with h= 6R) can be applied to point Q(which, however, is only at a height of R) yielding the condition gRvgR6710bg=+com2which gives us vgRcom2=507. Recalling previous remarks about the radial acceleration, Newton’s second law applied to the horizontal axis at Qleads to ()2com507vgRNmmRrRr==−−which (for Rr>>) gives4225050(2.80 10 kg)(9.80 m/s )1.96 10 N.77mgN−−×≈==×(b) The direction is toward the center of the loop. 8. Using the floor as the reference position for computing potential energy, mechanical energy conservation leads to 22releasetoptopcom112.UKUmghmvImgRω¡+Substituting Imr=252(Table 10-2(f)) and =vrcom(Eq. 11-2), we obtain 22comcom
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