ch11-p010 - M = 0.50 kg and R = 0.060 m into Eq. 11-10 and...

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10. We plug a = – 3.5 m/s 2 (where the magnitude of this number was estimated from the “rise over run” in the graph), θ = 30º,
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Unformatted text preview: M = 0.50 kg and R = 0.060 m into Eq. 11-10 and solve for the rotational inertia. We find I = 7.2 10 4 kg . m 2 ....
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