ch11-p014 - equations of Chapter 4. With v o y = 0 (and...

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mechanical energy on the plateau is equal to the mechanical energy at P . With Eq. 11-5, we obtain 1 2 mv 2 + 1 2 I com ω 2 + mgh 1 = 1 2 mv p 2 + 1 2 I com p 2 Using item ( f ) of Table 10-2, Eq. 11-2, and our expression (above) v 2 = gd 2 /2 h , we obtain gd 2 /2 h + 10 gh 1 /7 = v p 2 which yields (using the values stated in the problem) v p = 1.34 m/s. 14. To find the center of mass speed v on the plateau, we use the projectile motion
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Unformatted text preview: equations of Chapter 4. With v o y = 0 (and using “ h ” for h 2 ) Eq. 4-22 gives the time-of-flight as t = 2 h/g . Then Eq. 4-21 (squared, and using d for the horizontal displacement) gives v 2 = gd 2 /2 h . Now, to find the speed v p at point P , we apply energy conservation, i.e.,...
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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