(b) Now GGG′=−rrrowhere oˆˆ2.0i 2.0j.r−GTherefore, in the above expression, we set 5.0,2.0,0,30,60xyzvv′′′==−=and vz=0 . We get ()22ˆ(7.2 10 kg m s)k.mr v′=×=×⋅GGGA26. If we write G′ =′+′+′rxyz###ijk,then (using Eq. 3-30) we find GG′ =rvis equal to ′− ′+′−′+′−′yvzvxvzyxzy xdibg###.ijk(a) Here, ′ =where 3.0i4.0j.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.