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28. We note that the component of
G
v
perpendicular to
G
r
has magnitude
v
sin
θ
2
where
2
= 30°. A similar observation applies to
G
F
.
(a) Eq. 1120 leads to
()
(
)
(
)
2
3.0 m 2.0 kg 4.0 m/s sin30
12 kg m s.
rmv
⊥
==
°
=⋅
A
(b) Using the righthand rule for vector products, we find
G
G
rp
×
points out of the page, or
along the +
z
axis, perpendicular to the plane of the figure.
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 Spring '08
 Any
 Physics

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