28. We note that the component of Gvperpendicular to Grhas magnitude vsin θ2where 2= 30°. A similar observation applies to GF.(a) Eq. 11-20 leads to ()()()23.0 m 2.0 kg 4.0 m/s sin3012 kg m s.rmv⊥==°=⋅A(b) Using the right-hand rule for vector products, we find GGrp×points out of the page, or along the +zaxis, perpendicular to the plane of the figure.
This is the end of the preview. Sign up
access the rest of the document.