ch11-p035 - derivative to the (single) torque) then yields...

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35. (a) We note that dr v dt = G G = 8.0 t i ^ – (2.0 + 12 t )j ^ with SI units understood. From Eq. 11-18 (for the angular momentum) and Eq. 3-30, we find the particle’s angular momentum is 8 t 2 k ^ . Using Eq. 11-23 (relating its time-
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Unformatted text preview: derivative to the (single) torque) then yields = (48 t k ^ ) N m . (b) From our (intermediate) result in part (a), we see the angular momentum increases in proportion to t 2 ....
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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