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1
2
(0.500 rev)(2 rad/rev)
4.49 rad/s
0.700 s
(1.00 rev)(2 rad/rev)
8.98 rad/s.
0.700 s
π
ω
==
Treating each arm as a thin rod of mass 4.0 kg and length 0.60 m, the angular momenta
of the two arms are
22
2
11
1
2
2
(4.0 kg)(0.60 m) (4.49rad/s)
6.46 kg m /s
(4.0 kg)(0.60 m) (8.98rad/s) 12.92 kg m /s.
LI
m
r
m
r
ωω
=
=
⋅
=
=
⋅
From the athlete’s reference frame, one arm rotates clockwise, while the other rotates
counterclockwise. Thus, the total angular momentum about the common rotation axis
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 Spring '08
 Any
 Physics, Inertia

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