Ch11-p064 - 64 The aerialist is in extended position with I1 = 19.9 kg m 2 during the first and last quarter of the turn so the total angle rotated

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64. The aerialist is in extended position with 2 1 19.9 kg m I =⋅ during the first and last quarter of the turn, so the total angle rotated in 1 t is 1 0.500 rev. θ = In 2 t he is in a tuck position with 2 2 3.93 kg m I , and the total angle rotated is 2 3.500 rev. = Since there is no external torque about his center of mass, angular momentum is conserved, 11 2 2 I I ωω = . Therefore, the total flight time can be written as
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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