85. (a) In terms of the radius of gyration k, the rotational inertia of the merry-go-round is I = Mk2. We obtain I= (180 kg) (0.910 m)2= 149 kg⋅m2.(b) An object moving along a straight line has angular momentum about any point that is not on the line. The magnitude of the angular momentum of the child about the center of the merry-go-round is given by Eq. 11-21, mvR, where Ris the radius of the merry-go-round. Therefore, GLchild2kgm smkg m / s.==⋅44 0300120158...bgbgbg(c) No external torques act on the system consisting of the child and the merry-go-round,
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.