ch11-p085 - 85. (a) In terms of the radius of gyration k,...

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85. (a) In terms of the radius of gyration k , the rotational inertia of the merry-go-round is I = Mk 2 . We obtain I = (180 kg) (0.910 m) 2 = 149 kg m 2 . (b) An object moving along a straight line has angular momentum about any point that is not on the line. The magnitude of the angular momentum of the child about the center of the merry-go-round is given by Eq. 11-21, mvR , where R is the radius of the merry-go- round. Therefore, G L child 2 kg m s m kg m / s. == 44 0 300 120 158 .. . bg b g b g (c) No external torques act on the system consisting of the child and the merry-go-round,
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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