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89. We note that its mass is
M
= 36/9.8 = 3.67 kg and its rotational inertia is
IM
R
com
=
2
5
2
(Table 102(f)).
(a) Using Eq. 112, Eq. 115 becomes
2
22
2
2
2
com
com
com
com
com
111
2
17
222
5
2
1
0
v
K
I
Mv
MR
Mv
Mv
R
ω
§·
=+
=
+
=
¨¸
©¹
which yields
K
= 61.7 J for
v
com
= 4.9 m/s.
(b) This kinetic energy turns into potential energy
Mgh
at some height
h = d
sin
θ
where
the sphere comes to rest. Therefore, we find the distance traveled up the
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 Spring '08
 Any
 Physics, Inertia, Mass

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