ch11-p094 - 94(a With p = mv = 16 j kg m s we take the...

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94. (a) With G G pm v == 16 # , j kg m s we take the vector cross product (using either Eq. 3-30 or, more simply, Eq. 11-20 and the right-hand rule): 2 ˆ (3 2k gm/ s ) k . rp =× =− G GG A (b) Now the axis passes through the point G R = 40 . # j m, parallel with the z axis. With G G G =− = rr R 20 . # i m, we again take the cross product and arrive at the same result as
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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