ch11-p094 - 94. (a) With p = mv = 16 j kg m s , we take the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
94. (a) With G G pm v == 16 # , j kg m s we take the vector cross product (using either Eq. 3-30 or, more simply, Eq. 11-20 and the right-hand rule): 2 ˆ (3 2k gm/ s ) k . rp =× =− G GG A (b) Now the axis passes through the point G R = 40 . # j m, parallel with the z axis. With G G G =− = rr R 20 . # i m, we again take the cross product and arrive at the same result as
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online