94. (a) With GGpmv==−⋅16#,j kg m s we take the vector cross product (using either Eq. 3-30 or, more simply, Eq. 11-20 and the right-hand rule): 2ˆ(32kgm/s)k.rp=× =−⋅GGGA(b) Now the axis passes through the point GR=40.#j m, parallel with the zaxis. With GGG′=− =rrR20.#i m, we again take the cross product and arrive at the same result as
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