px= pcos θpy= psin wherep= 2.4 (SI units understood) and = 115°. The mass (0.80 kg) given in the problem is not used in the solution. Thus, with x= 2.0, y= 3.0 and the momentum components described above, we obtain 2ˆ(7.4kg m s)k.rp=× =⋅GGGA98. This problem involves the vector cross product of vectors lying in the
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.