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p
x
=
p
cos
θ
p
y
=
p
sin
where
p
= 2.4 (SI units understood) and
= 115°. The mass (0.80 kg) given in the
problem is not used in the solution. Thus, with
x
= 2.0,
y
= 3.0 and the momentum
components described above, we obtain
2
ˆ
(7.4kg m s)k.
rp
=× =
⋅
G
GG
A
98. This problem involves the vector cross product of vectors lying in the
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Momentum

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