ch12-p001 - 1. (a) The center of mass is given by xcom = 0...

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1. (a) The center of mass is given by com 000() ( 2 . 0 0 m )() ( 2 . 0 0 m ( 2 . 0 0 m ) 1.00 m. 6 mmm x m +++ + + == (b) Similarly, we have com 0 ( )(2.00 m) ( )(4.00 m) ( )(4.00 m) ( )(2.00 m) 0 2.00 m. 6 mmmm y m +++++ (c) Using Eq. 12-14 and noting that the gravitational effects are different at the different locations in this problem, we have 6 1 111 222 333 444 555 666 cog 6 11 22 33 44 55 66 1 0.987 m.
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