1. (a) The center of mass is given by com000()(2.00m)()(2.00m(2.00m)1.00 m.6mmmxm+++++==(b) Similarly, we have com0 ( )(2.00 m) ( )(4.00 m) ( )(4.00 m) ( )(2.00 m) 02.00 m.6mmmmym+++++(c) Using Eq. 12-14 and noting that the gravitational effects are different at the different locations in this problem, we have 61111222333444555666cog611223344556610.987 m.
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