ch12-p003 - 3. The object exerts a downward force of...

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Unformatted text preview: 3. The object exerts a downward force of magnitude F = 3160 N at the midpoint of the rope, causing a “kink” similar to that shown for problem 10 (see the figure that accompanies that problem). By analyzing the forces at the “kink” where F is exerted, we find (since the acceleration is zero) 2T sinθ = F, where θ is the angle (taken positive) between each segment of the string and its “relaxed” position (when the two segments are colinear). In this problem, we have θ = tan −1 Therefore, T = F/(2sinθ ) = 7.92 × 103 N. 0.35 m = 11.5°. 1.72 m ...
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