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22
23
1
12
2
(80kg)(9.8m/s )(3.5m)+(60kg)(9.8m/s )(2.5m)
5.0m
8.4 10 N.
ws
mg
F
+
==
+
=×
AA
(b) Equilibrium of forces leads to
(60kg+80kg)(9.8m/s ) 1.4 10 N
sw
FF m
gm
g
+=
+
=
which (using our result from part (a)) yields
F
2
2
53 10
.N
.
8. Let
A
1
15
=
.ma
n
d
2
(5.0 1.5) m 3.5 m
=−
=
A
. We denote tension in the cable closer to
the window as
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force, Gravity

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