ch12-p021 - 21. We consider the wheel as it leaves the...

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We calculate the torque around the step corner. The second diagram indicates that the distance from the line of F to the corner is r h , where r is the radius of the wheel and h is the height of the step. The distance from the line of mg to the corner is rr h r h h 2 2 2 2 +− = b g . Thus, Fr h mg rh h −− − = bg 20 2 . The solution for F is 22 2 2 2 2 2(6.00 10 m)(3.00 10 m) (3.00 10 m) 2 = (0.800 kg)(9.80 m/s ) (6.00 10 m) (3.00 10 m) 13.6 N. rh h Fm g rh ×× × = −× × = 21. We consider the wheel as it leaves the lower floor. The floor no longer exerts a force
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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