ch12-p029 - 29. The bar is in equilibrium, so the forces...

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29. The bar is in equilibrium, so the forces and the torques acting on it each sum to zero. Let T l be the tension force of the left–hand cord, T r be the tension force of the right–hand cord, and m be the mass of the bar. The equations for equilibrium are: vertical force components horizontal force components torques cos cos 0 sin sin 0 cos 0. lr r TTm g TT mgx T L θ φ θφ +− = −+ = −= The origin was chosen to be at the left end of the bar for purposes of calculating the torque. The unknown quantities are T l , T r , and x . We want to eliminate T l and T r , then solve for x . The second equation yields T l = T r sin /sin and when this is substituted
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