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Unformatted text preview: 32. (a) Computing torques about the hinge, we find the tension in the wire: TL sinθ − Wx = 0 T= Wx . L sinθ (b) The horizontal component of the tension is T cos θ, so equilibrium of horizontal forces requires that the horizontal component of the hinge force is Fx = FG Wx IJ cosθ = Wx . L tanθ H L sinθ K
FG Wx IJ sinθ = W FG1 − x IJ . H LK H L sinθ K (c) The vertical component of the tension is T sin θ, so equilibrium of vertical forces requires that the vertical component of the hinge force is
Fy = W − ...
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