ch12-p033 - 33. We examine the box when it is about to tip....

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
33. We examine the box when it is about to tip. Since it will rotate about the lower right edge, that is where the normal force of the floor is exerted. This force is labeled N F on the diagram below. The force of friction is denoted by f , the applied force by F , and the force of gravity by W . Note that the force of gravity is applied at the center of the box. When the minimum force is applied the box does not accelerate, so the sum of the horizontal force components vanishes: F f = 0, the sum of the vertical force components vanishes: 0 N FW −= , and the sum of the torques vanishes: FL WL /2 = 0. Here L is the length of a side of the box and the origin was chosen to be at the lower right edge. (a) From the torque equation, we find 890 N 445N. 22 W F == = (b) The coefficient of static friction must be large enough that the box does not slip. The
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Page1 / 2

ch12-p033 - 33. We examine the box when it is about to tip....

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online