ch12-p034 - 34 As shown in the free-body diagram the forces...

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2 (70 kg)(9.8 m/s )(0.20 m) 17 N. 4 4(2.0 m) h mga F H == (b) From the y -component of the force equation, we obtain 2 2 (70 kg)(9.8 m/s ) 1.7 10 N. 44 v mg F × 34. As shown in the free-body diagram, the forces on the climber consist of the normal force from the wall, the vertical component v F and the horizontal component h F of the force acting on her four fingertips, and the downward gravitational force mg . Since the climber is in static equilibrium, the net force acting on her is zero.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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